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Chapter 7: Introduction to Rings

7.1 Basic Definitions and Examples

Definition:

Definition: A ring RR with identity 11 with 101\neq 0 is called a division ring or skew field if a1,aR\exists a^{-1},\forall a\in R with a0a\neq 0, such that aa1=a1a=1aa^{-1}=a^{-1}a=1. A commutative division ring is called a field.
Proposition 1: Let RR be a ring and a,bRa,b\in R. Then

Definition: Let RR be a ring.

Definition: A commutative ring with identity 101 \neq 0 is called an integral domain if it has no zero divisors (Z\mathbb{Z}-like).
Proposition 2: Assume a,b,cRa,b,c\in R with element aa not a zero divisor. If ab=acab=ac, then either a=0a=0 or b=cb=c. In particular, if RR is an integral domain, ab=ac    a=0ab=ac\implies a=0 or b=cb=c.
Corollary 3: Any finite integral domain is a field. A result that follows is a finite division ring is necessarily commutative, i.e. a field. This won't be proven.
Definition: (Subring Criterion) A subring of the ring RR is a subgroup of RR that is closed under multiplication. The subring criterion is showing that it is nonempty and closed under subtraction and under multiplication.

7.2 Examples: Polynomial Rings, Matrix Rings, and Groups Rings

Polynomial Rings: RR[x]R\in R[x] as the constant polynomials. Addition is done component-wise in R[x]R[x]. R[x]R[x] is a commutative ring with identity.
Proposition 4: Let RR be an integral domain and let nonzero p(x),q(x)R[x]p(x),q(x)\in R[x]. Then

Matrix Rings: Mn(R)M_{n}(R) is the set of all n×nn\times n matrices with entries from RR. If RR is nontrivial and n2n\geq2 then Mn(R)M_{n}(R) is non-commutative. An element (aij)Mn(R)(a_{ij})\in M_{n}(R) is called a scalar matrix if it is diagonal, and the set of scalar matrices is a subring of Mn(R)M_{n}(R) and is isomorphic to RR. If RR has an identity 11, then the identity IMn(R)I\in M_{n}(R) and the subgroup of units in Mn(R)M_{n}(R) is GLn(R)GL_{n}(R). If a ring SRS\subseteq R then Mn(S)Mn(R)M_{n}(S)\subseteq M_{n}(R) (and is also a subring).
Group Rings: Fix a commutative ring RR with nonzero identity 11 and let GG be a finite group {g1,,gn}\{ g_{1},\dots,g_{n} \}. The group ring RGRG of GG with coefficients in RR to be the set of all formal sums a1g1+angn,  aiRa_{1}g_{1}+\dots a_{n}g_{n},\;a_{i}\in R. Multiplication is defined by (agi)(bgj)=(ab)gk(ag_{i})(bg_{j})=(ab)g_{k}, where gigj=gkg_{i}g_{j}=g_{k}. RGRG is commutative     \iff GG is abelian. If SRS\subseteq R then SGRGSG\subseteq RG. If HGH\leq G then RHRGRH\subseteq RG. The set of all elements of RGRG whose coefficients sum to zero is a subring without identity. If G>1\lvert G \rvert>1, the set of elements with zero "constant term" (coefficient of identity in GG is 00) is not a subring (not closed under multiplication).

7.3 Ring Homomorphisms and Quotient Rings

Definition: Let R,SR,S be rings.

Proposition 5: Let R,SR,S be rings and φ:RS\varphi:R\to S be a homomorphism.

Definition: Let RR be a ring, IRI\subseteq R, and rRr\in R.

Fact: (Ideal Criterion) II is an ideal if it is nonempty, closed under subtraction, and closed under multiplication by all elements of RR.
Proposition 6: Let RR be a ring and let II be an ideal of RR. Then the additive quotient R/IR/I is a ring under the binary operations (r+I)+(s+I)=(r+s)+I(r+I)+(s+I)=(r+s)+I and (r+I)×(s+I)=(rs)+I(r+I)\times(s+I)=(rs)+I. The converse holds true too. R/IR/I is a quotient ring.
Theorem 7:

Theorem 8: Let RR be a ring.

Definition: Let I,JI,J be ideals of RR. I+J={a+baI,bJ}I+J=\{ a+b\mid a\in I,b\in J \}, IJ={abaI,bJ}IJ=\left\{ \sum ab\mid a\in I,b\in J \right\}. In={a1anaiI,in}I^{n}=\left\{ \sum a_{1}\dots a_{n} \mid a_{i}\in I,\leq i\leq n \right\}.

7.4 Properties of Ideals

Definition: Let ARA\subseteq R.

Proposition 9: Let II be an ideal of RR.

Corollary 10: If RR is a field then any nonzero ring homomorphism from RR into another ring is an injection.
Definition: An ideal MM in a ring SS is maximal if MSM \neq S and the only ideals containing MM are MM and SS.
Proposition 11: In a ring with identity every proper ideal is contained in a maximal ideal.
Proposition 12: Assume RR is commutative. The ideal MM is maximal     \iff R/MR/M is a field.
Definition: Assume RR is commutative. An ideal PP is prime if PRP \neq R and whenever abPab\in P when a,bRa,b\in R, at least one of a,bPa,b\in P.
Proposition 13: Assume RR is commutative. Then the ideal PP is a prime ideal in RR     \iff R/PR/P is an integral domain.
Corollary 14: Assume RR is commutative. Every maximal ideal of RR is prime

7.5 Rings of Fractions

Theorem 15: Let RR be a commutative ring. Let DD be any nonempty subset of RR that does not contain 00, does not contain any zero divisors, and is closed under multiplication (i.e., abD,  a,bDab\in D,\;\forall a,b\in D). Then there is a commutative ring QQ with 11 such that RQR\leq Q and dD\forall d\in D, dd is a unit in QQ. The ring QQ has the following additional properties.

Definition: Let R,D,QR,D,Q be as in Theorem 15.

Fact: If AFA\subseteq F, the intersection of all subfields of FF containing AA is a subfield of FF and is denoted the subfield generated by AA. This subfield is the smallest subfield of FF containing AA, where size is defined analogously as in Theorem 15.
Corollary 16: Let RR be an integral domain and let QQ be the field of fractions of RR. If a field FF contains a subring RRR'\cong R then the subfield of FF generated by RR' is isomorphic to QQ.

7.6 The Chinese Remainder Theorem

Definition: The ideals A,BA,B of the ring RR are comaximal if A+B=RA+B=R.
Theorem 17: (Chinese Remainder Theorem) Let A1,,AkA_{1},\dots,A_{k} be ideals in RR. The map RR/A1××R/AkR\to R/A_{1}\times\dots \times R/A_{k} defined by r(r+A1,,r+Ak)r\mapsto(r+A_{1},\dots,r+A_{k}) is a ring homomorphism with kernel i=1kAi\bigcap_{i=1}^kA_{i}. If i,j{1,,k}\forall i,j\in \{ 1,\dots,k \} with iji \neq j we have Ai+Aj=RA_{i}+A_{j}=R, then the map is surjective and i=1kAi=A1Ak=i=1kAi\bigcap_{i=1}^kA_{i}=A_{1}\dots A_{k}=\prod_{i=1}^kA_{i}. Thus, R/(A1Ak)=R/(A1Ak)R/A1××R/AkR/(A_{1}\dots A_{k})=R/(A_{1}\cap\dots \cap A_{k})\cong R/A_{1}\times \dots \times R/A_{k}.
Corollary 18: Let nZ+n\in \mathbb{Z}^+ and let p1a1pkakp_{1}^{a_{1}}\dots p_{k}^{a_{k}} be its prime factorization. Then Z/nZ(Z/p1a1Z)××(Z/pkakZ)\mathbb{Z}/n\mathbb{Z}\cong(\mathbb{Z}/p_{1}^{a_{1}}\mathbb{Z})\times\dots \times(\mathbb{Z}/p_{k}^{a_{k}}\mathbb{Z}) as rings. In particular, for multiplicative groups, (Z/nZ)×(Z/p1a1Z)×××(Z/pkakZ)×(\mathbb{Z}/n\mathbb{Z})^{\times}\cong(\mathbb{Z}/p_{1}^{a_{1}}\mathbb{Z})^{\times}\times\dots \times (\mathbb{Z}/p_{k}^{a_{k}}\mathbb{Z})^{\times}.